The equation for determining the download time for a peer-to-peer file sharing is given below. Dpsp ≥ max(F/us, F/dmin, NF/(us + Σ_{i=1}^{N} ui)) Using the same terms, give an equation for the minimum download time for a client/server file download.
Try an answer before revealing the guidance below.
Key Concepts
- Server uploads every copy
- NF/us
- F/dmin
- Bottleneck
Answer Approach
- In client-server, only the server uploads: how many copies must it send?
- Keep the slowest-client download constraint.
- The distribution time is bounded by the larger of the two.
Full Answer
Answer status: Verified against study notes. Revision notes, not an official marking scheme.
D_cs ≥ max(NF/us, F/dmin). The server alone must upload N copies (NF/us), and the slowest client must still download one copy (F/dmin); the distribution time is at least the larger of these.
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